27b^2+39bc+14c^2=

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Solution for 27b^2+39bc+14c^2= equation:


Simplifying
27b2 + 39bc + 14c2 = 0

Reorder the terms:
39bc + 27b2 + 14c2 = 0

Solving
39bc + 27b2 + 14c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3b + 2c)(9b + 7c) = 0

Subproblem 1

Set the factor '(3b + 2c)' equal to zero and attempt to solve: Simplifying 3b + 2c = 0 Solving 3b + 2c = 0 Move all terms containing b to the left, all other terms to the right. Add '-2c' to each side of the equation. 3b + 2c + -2c = 0 + -2c Combine like terms: 2c + -2c = 0 3b + 0 = 0 + -2c 3b = 0 + -2c Remove the zero: 3b = -2c Divide each side by '3'. b = -0.6666666667c Simplifying b = -0.6666666667c

Subproblem 2

Set the factor '(9b + 7c)' equal to zero and attempt to solve: Simplifying 9b + 7c = 0 Solving 9b + 7c = 0 Move all terms containing b to the left, all other terms to the right. Add '-7c' to each side of the equation. 9b + 7c + -7c = 0 + -7c Combine like terms: 7c + -7c = 0 9b + 0 = 0 + -7c 9b = 0 + -7c Remove the zero: 9b = -7c Divide each side by '9'. b = -0.7777777778c Simplifying b = -0.7777777778c

Solution

b = {-0.6666666667c, -0.7777777778c}

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